fnord_disc

The areas where you get those plunging shots are annoyingly small though, it's more likely you get a bunch of superstructure or casemate penetrations.

I think Saipan is a great design and looks like oodles of fun, but I don't play American carriers. I have no use for it.

Did you get a detonation medal and the detonation signal flags? If you did, then you're just really unlucky and there's nothing you could do. Torpedo hits have a chance of ~1% to detonate your magazine when they hit.

A Zuikaku premium would kind of suck though because it's just a slightly upgraded Shokaku. There are a lot of premiums that make more sense, like CV Ibuki. As much as my wallet would cry, I'd rather have an Akagi/Kaga premium than not at all.

Haruna looks pretty unoffensive with black and yellow. Hiei is hard to look at, though...

They're almost identical anyway. It's not like Soryu and Hiryu where Hiryu is basically a different ship altogether. I mean, I know there are potential premiums in the mid tiers, but there aren't any I can buy :3

Thanks. I really want a Japanese premium around T6 or T7, but, yeah...

Is there any word on Tone or a Japanese premium carrier?

I need about 1m damage, which should be easily achievable within 20 games or so.

No they can't. If you turn the ship early enough you will not eat more then 4 torpedoes in a battleship from a 4+4 cross drop. Save the damage control for the dive bombers so you repair the fire and you survive with about 40% HP in most cases, about half of which you can repair. You cannot avoid being damaged by carriers, but if you get deleted, you made a mistake. 350k damage rounds are only possible because the enemy is horrible.

Is there any news on Tone? And I'm not talking about the Chinese and their lulzy server.

Ohhh, now I see where the problem was. I assumed you meant the physical characters of drag in flight. The solution of the differential equation for velocity (~sqr(penetration)) with drag over time is of the form v=A*e^(-k*t) with v_0 and drag coefficient and m and so on filling up the constants. WG can arbitrarily add other constants into the k if they want to modify the flight behavior of shells in some way for balancing purposes. For example, battleship shells in the game are significantly faster than they should be at all ranges compared to other projectiles, but at short to medium range their behavior should be almost indistinguishable from medium calibers.

With some cruisers, yes, he is not bad. But he has a 36% WR with Cleveland, from 77 games, so I don't even.

Then I don't understand why you said that the light shell suffers less drag. The opposite is true. Nah, that's only for sideways drag i.e. loss in reference frame speed. It's for the sideways offset. Drag from front acts on the cone shape and depending on your cone your Cd changes. Just imagine a cylinder flying through the air. Frontal drag is obviously higher than an aerodynamically shaped shell.

I don't play American carriers so I hope they spit out a Japanese one. Would totally buy it.

The mass is not relevant for drag. It simply isn't, in no physical context. The mass affects the kinetic energy of the projectile and since F=ma a heavier projectile will suffer less drag acceleration, but there is no way that mass affects the force of the drag. If less weight produced less drag like you propose, an extremely light but rather large object would suffer very little drag. This cannot be. How do parachutes work? Can you explain to me why less weight should physically reduce drag? edit: The drag coefficient does not depend on weight; it depends on the shape of the cross-section and is a dimensionless number. A low drag coefficient is a result of designing a good cone shape for the shell. It's a feat of aerodynamic engineering and has nothing to do with mass at all.

If anything, it means a fast but light shell loses penetration even quadratically faster than a heavy shell, i.e. much faster and not just somewhat faster. This can be estimated and compared to the experimental data quite easily. US shell has 762 m/s muzzle velocity, German shell has 925 m/s. Since the shells have the basically same shape and cross section, we can say that the German shell suffers 925^2/762^2=47% more drag. Of course, the American shell suffers drag for longer because it spends more time in the air, but it will never dip below the German values. Anyway, if we look at those navweaps values, the American shell loses about 40% its penetration between 10km and 20km and the German shell loses about 60%, so it roughly corresponds to the 47% increased drag we calculated for v_0... the correct calculation would involve a differential equation and I'm too lazy for MATLAB right now.

Shouldn't it be the other way around? A heavy shell conserves kinetic energy better than a light shell over long distances. If you look at navweaps, that's exactly what it shows. German fast 125kg 20.3cm is 240mm @ 9.5km and 100mm @ 20km. American 152kg 20.3cm is 254mm @ 9.88km and 152mm @ 19km or 127mm @ 22.3km. Besides, air drag does not depend on weight... that should be pretty obvious. Why should it? edit: Maybe you're not interpreting the formula for drag correctly: the rho is the density of the gas or fluid that produces the drag, not the density of the shell. Drag is linearly dependant on cross-section of object, quadratically dependant on object speed and linearly dependant on the drag coefficient (a scalar for the shape of the object).

Normalization is an "effect" that mostly depends on AP shell nose design, so for all intents and purposes (because gunnery trial archives are not very good) WG can invent these values as they want. I guess they decided German shells don't normalize well... Frankly, I think all these values are still too low. In my opinion armor angling is a silly and unhistorical mechanic and shouldn't be as powerful as it is. Just think: crossing the T was historically a death sentence for the lower bar of the T, whereas in WoWs it's a death-by-citadel sentence for the upper bar of the T, a complete reversal of historical reality. Makes you scratch your head.

fnord_disc Do not believe Acheron's lies.

I would only stick around if you're certain you can "make it work", i.e. there's a really nice spot nearby where you can hide behind islands or something like that. Otherwise I'd agree you probably shouldn't run to the map edge though since resetting caps in domination or trying to decap once there aren't many ships left is very valuable. I mean, if the game had lasted almost the whole 20 minutes, then by the end there wouldn't be many ships left, so you can be pretty sure whether capping one of the points is safe or not. Of course, you need the mod that displays the last known position of enemies... edit: It depends a little on the map in my opinion. Two Brothers for instance has almost completely isolated cap points and high islands for cover, so you can easily cap in safety. False Dawn is quite open and very dangerous... 141 HP is not enough for that. Even an Umikaze will you with guns.

I'd like to point out that you can get Tirpitz concealment quite low with the skill, camo and the upgrade. How low? 11.9km surface. Think about it.

There is no RNG in torpedo hits.

Btw, if he's German, he won't find it. The button has a different label on German keyboards (but it works the same way). Let's wait and see.

Are you stupid?